10p^2=980

Solution for 10p^2=980 equation:

10p^2=980

We move all terms to the left:

10p^2-(980)=0

a = 10; b = 0; c = -980;
Δ = b2-4ac
Δ = 02-4·10·(-980)
Δ = 39200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39200}=\sqrt{19600*2}=\sqrt{19600}*\sqrt{2}=140\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140\sqrt{2}}{2*10}=\frac{0-140\sqrt{2}}{20}
=-\frac{140\sqrt{2}}{20}
=-7\sqrt{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140\sqrt{2}}{2*10}=\frac{0+140\sqrt{2}}{20}
=\frac{140\sqrt{2}}{20}
=7\sqrt{2}
$